Lab 07: magnetic force on a wire
WebPhysics 104L/205L Magnetic Force. Revised June 2024 Page 1 of 1. Purpose: To verify the formula for determin ing magnetic force on a current carrying wire. Apparatus: Pivot Interactive Magnetic Force Lab Excel Introduction: Conductors carrying currents experience forces when placed in a region of magnetic field. In general, the force depends on the … WebBalancing the Gravitational and Magnetic Forces on a Current-Carrying Wire. A wire of length 50 cm and mass 10 g is suspended in a horizontal plane by a pair of flexible leads ( Figure …
Lab 07: magnetic force on a wire
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WebJul 21, 2024 · Question 2: Calculate the force on the wire, given B = 1.50 T, l = 5.00 cm, and I = 20.0 A. The angle between the current and the magnetic field is 90°. Answer: The force … WebLab 07: Magnetic Force on a Wire. The data for the experiment is given for this lab. Answer the following questions as you work through the lab. Write your answers in blue. (Note …
WebDetailed explanation of force applied by magnetic field on a current carrying straight wire and arbitrary shaped wire. Derivation for the formula of force an... WebThe magnetic force on a current-carrying wire in a magnetic field is given by F → = I l → × B →. For part a, since the current and magnetic field are perpendicular in this problem, we can simplify the formula to give us the magnitude and find the direction through the RHR-1. The angle θ is 90 degrees, which means sin θ = 1.
WebSep 12, 2024 · Figure 12.4. 1: (a) The magnetic field produced by a long straight conductor is perpendicular to a parallel conductor, as indicated by right-hand rule (RHR)-2. (b) A view from above of the two wires shown in (a), with one magnetic field line shown for wire 1. RHR-1 shows that the force between the parallel conductors is attractive when the ... WebThe magnetic force on the wire is: F = BIL Where: F = magnetic force (N) B = magnetic flux density (T) I = current (A) L = length of the wire (m) Since F = mg where m is the mass in kilograms, equating these gives: mg = BIL Rearranging for m: Comparing this to the straight-line equation: y = mx + c y = m (mass) x = I m = BL / g c = 0
WebThe magnetic force, F, on a current-carrying wire F = IL × B or F = ILB sin θ depends on the current through the wire, I, the length of wire in the magnetic field, L, the magnitude of the magnetic field, B, and, since L and B are vectors, the angle θ …
WebAdvanced Physics questions and answers. Magnetic Force on a Wire Lab Fine N Current in the wire goes into the page in this picture A) Faire (pushing the magnet down, due to Newton's 3rd Law) Part A - Changing Current (1) Use the plate that has the longest horizontal wire (438) Set up the apparatus, making sure that the wire is directly in ... is deer a wild animalWebQuestion: 8:07 va LTE EXPERIMENT 31 (LAB 10) - Magnetic... Theory A current-carrying wire generates a magnetic field surrounding the wire. When a permanent magnet is placed in the magnetic field of the wire, it experiences a force due to the interaction between the two magnetic ficlds. rwjpe franklin family practiceWebMay 9, 2024 · The net force on a current-carrying loop of wire in a uniform magnetic field is zero. Note that this does not preclude the possibility that the rigid loop rotates; for … rwjpe obgyn specialty care officeWebMagnetic Force. The magnetic field B is defined from the Lorentz Force Law, and specifically from the magnetic force on a moving charge: The implications of this expression include: 1. The force is perpendicular to both the velocity v of the charge q and the magnetic field B. 2. The magnitude of the force is F = qvB sinθ where θ is the angle ... rwjpe east brunswick primary careWebJan 27, 2006 · A magnetic force is created when a current passes through the circuit board wire loop. This force acts on the permanent magnet assembly causing a change in its … rwjpe new brunswick cardiology grouprwjpe dayton medical group dayton njWebThe force on the wire is given by F = I L × B. The direction of L × B is the negative y-direction. Since L and B are perpendicular to each other, the magnitude F = ILB. Details of the calculation: F = ILB = (2.4 A) (0.75 m) (1.6 T) = 2.88 N. The force on the section of wire is F = -2.88 N j, in the negative y-direction. rwjpe cardiology associates of new brunswick