WebIf p and q are the roots of the equation x 2 − px + q = 0, then Options p = 1, q = −2 p = 1, q = 0 p = −2, q = 0 p = −2, q = 1 Advertisement Remove all ads Solution Since, p and q … WebIf α and β are the zeros of the quadratic polynomial f(x) = x 2 + px + q `alpha+beta="-coefficient of x"/("coefficient of "x^2)` `=(-p)/1` `alphabeta="constant term"/("coefficient of "x^2)` `=q/1` = q. Let S and P denote respectively the sums and product of the zeros of the polynomial whose zeros are (α + β) 2 and (α − β) 2. S = (α ...
If 2 and ½ are the zeros of px 2+5x+r, then - teachoo
Web16 okt. 2024 · Answer: Option (B), E = q² - p² is correct. Step-by-step explanation: The given polynomials are f (x) = x² + px + 1 g (x) = x² + qx + 1 Since a, b are the zeroes of f (x), a + b = - p ..... (1) ab = 1 ..... (2) Since c, d are the zeroes of g (x), c + d = - q ..... (3) cd = 1 ..... (4) Now, E = (a - c) (b - c) (a + d) (b + d) WebSolution Verified by Toppr Correct option is C) α and β are the roots of x 2+px+q=0 So, α+β= 1−p=−p and αβ= 1q=q Let α1 and β1 be the roots of new polynomial g(x) So, sum of roots = α1+ β1= αβα+β= q−p and product of roots αβ1 = q1 So, g(x)=x 2− (sum of roots) x+ (product of roots) So, g(x)=x 2−( q−p)x+ q1 So, g(x)=qx 2+px+1 The answer is option (C) ribs shell holder
Solve x^2-px+q=0 Microsoft Math Solver
WebSimilar Problems from Web Search. Go back to the initial equation: x2 −px+ 0 = x(x− p) = 0 has roots p and 0 for all p ∈ R. So it works for any p. Find p and q such that the maximum and minimum values of 5+ 6cosθ +2cos2θ satisfy x2 − px+q = 2. The minimum value is wrong. Let f (t) = 5+ 6t +2(2t2 − 1). [Recall that cos(2x) = 2cos2x ... Web29 mrt. 2024 · Transcript. Question 38 If 2 and ½ are the zeros of px 2+5x+r, then (a) p = r = 2 (b) p = r = −2 (c) p = 2, r= −2 (d) p = −2, r = 2 Let p(x) = px2 + 5x + r Since 2 and ½ are zero of p(x) p(2) = 0 p(2)2 + 5(2) + r = 0 4p + 10 + r 4p + r = −10 p(𝟏/𝟐) = 0 p (𝟏/𝟐)^𝟐+ 5 (𝟏/𝟐) + r = 0 𝒑/𝟒+𝟓/𝟐+𝒓 = 0 Multiplying by 4 both sides p + 10 + 4r = 0 p + 4r = − ... Web13 jul. 2024 · If p and q are the roots of the equations x^2+px+q=0 then (a) p =1,q = –2 (b) p = 0,q = 2 (c) p = – 2,q = 0 (d) p = –2,q =1 To buy complete Course please V... AboutPressCopyrightContact ... red holland